Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.6 - Solving Miscellaneous Equations - Exercises - Page 34: 16

Answer

$x=0, x=\pm \sqrt 2$

Work Step by Step

$\frac{6x(x^{2}+1)^{2}(x^{2}+2)^{4}-8x(x^{2}+1)^{3}(x^{2}+2)^{3}}{(x^{2}+2)^{8}}=0$ $\frac{2x(x^{2}+1)^{2}(x^{2}+2)^{3}(3(x^{2}+2)-4(x^{2}+1))}{(x^{2}+2)^{8}}=0$ $\frac{2x(x^{2}+1)^{2}(x^{2}+2)^{3}(-x^{2}+2)}{(x^{2}+2)^{8}}=0$ $x=0, x=\pm \sqrt 2$
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