Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.3 - The Integral Test and Estimates of Sums - 11.3 Exercises - Page 726: 40

Answer

$N\geq e^{100}$

Work Step by Step

$\int_{N}^{\infty}\frac{1}{x(lnx)^{2}}dx\leq 0.01$ $[-\frac{1}{lnx}]_{N}^{\infty}\leq 0.01$ $-\frac{1}{ln\infty}-(-\frac{1}{lnN})\leq 0.01$ $\frac{1}{lnN}\leq \frac{1}{100}$ $lnN\geq 100$ Hence, $N\geq e^{100}$
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