Answer
Convergent
Work Step by Step
$\Sigma_{n=1}^{\infty} \frac{1}{n^{3}+n^{2}}\lt \Sigma_{n=1}^{\infty} \frac{1}{n^{2}}$
$\frac{1}{n^{2}}$ is a p-series with $p =2 >1$
Hence, the given series is convergent.
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 11 - Section 11.3 - The Integral Test and Estimates of Sums - 11.3 Exercises - Page 726: 25
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