Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.3 - The Integral Test and Estimates of Sums - 11.3 Exercises - Page 726: 31

Answer

Convergent for $p\lt -1$.

Work Step by Step

$\int_{1}^{\infty}x(1+x^{2})dx=\int_{2}^{\infty}\frac{1}{2}u^{p}du=\frac{1}{2}(\infty^{p}-2^{p})$ which is convergent for $p\lt -1$.
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