Answer
$f$ is concave up on $(−∞,∞)$. $x=-1$ is the only point of inflection.
Work Step by Step
$f'(x) = 8x^3 + 24x^2 + 24x − 1$, and $f''(x) = 24x^2 + 48x + 24 = 24(x + 1)^2$.
Note that this quantity is always greater than $0$ for $x \neq −1$, and is $0$ only at $x = −1$. Thus $f$ is concave up on $(−∞,−1)$ and on $(−1,∞)$, and since $f$ and $f'$ are continuous at $−1$, we can say that $f$ is concave up on $(−∞,∞)$.