Answer
$f$ is increasing on $(−∞,∞)$ and $f$ is never decreasing.
Work Step by Step
$f'(x) = \frac{1}{x^2+1}$, which is always positive, so $f$ is increasing on $(−∞,∞)$ .
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 4 - Applications of the Derivative - 4.2 What Derivatives Tell Us - 4.2 Exercises - Page 257: 31
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