Answer
$\frac{dy}{dx} = \frac{1}{xlog_2(x)ln^2(2)}$
Work Step by Step
$y = log_2(log_2(x))$
Chain Rule:
$\frac{dy}{dx} = \frac{1}{log_2(x)ln(2)} \times \frac{1}{xln(2)} = \frac{1}{xlog_2(x)ln^2(2)}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.9 Derivatives of Logarithmic and Exponential Functions - 3.9 Exercises - Page 211: 60
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