Answer
$s'(t) = -2^t\ln(2)\sin(2^t)$
Work Step by Step
If $f(x) = b^x$, then $f'(x) = b^xln(b)$
$s(t) = cos(2^t)$
Chain Rule:
$s'(t) = 2^tln(2)(-sin(2^t)) = -2^t\ln(2)\sin(2^t)$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.9 Derivatives of Logarithmic and Exponential Functions - 3.9 Exercises - Page 211: 38
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
