Answer
$\frac{dy}{dx} = \frac{-1}{x\ln(4)(\log_{4}(x))^2}$
Work Step by Step
$y = \frac{1}{\log_{4}(x)}$
Quotient Rule:
$\frac{dy}{dx} = \frac{(0)(\log_{4}(x))-(1)\left(\frac{1}{x\ln(4)}\right)}{(\log_{4}(x))^2} = \frac{-1}{x\ln(4)(\log_{4}(x))^2}$