Answer
$A' = 1000(1.045^{4t})ln(1.045)$
Work Step by Step
If $f(x) = b^x$, then $f'(x) = b^xln(b)$
$A = 250(1.045)^{4t}$
Chain Rule
$A' = 250\times1.045^{4t}ln(1.045)\times4 = 1000(1.045^{4t})ln(1.045)$
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