Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.9 Derivatives of Logarithmic and Exponential Functions - 3.9 Exercises - Page 211: 29

Answer

$A' = 1000(1.045^{4t})ln(1.045)$

Work Step by Step

If $f(x) = b^x$, then $f'(x) = b^xln(b)$ $A = 250(1.045)^{4t}$ Chain Rule $A' = 250\times1.045^{4t}ln(1.045)\times4 = 1000(1.045^{4t})ln(1.045)$
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