Answer
$y'= 6x-2-2e^{-2x}$
Work Step by Step
$y = 3x^2-2x+e^{-2x}$
Using Power Rule and $\frac{d}{dx}e^{nx}$ = $ne^{nx}$:
$y'=3(2)x^{(2-1)} - 2(1)x^{(1-1)}+(-2)e^{-2x} = 6x-2-2e^{-2x}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 46
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