Answer
$y'= 2s-2$
Work Step by Step
Quotient Rule:
$y = \frac{4s^3-8s^2+4s}{4s}$
$y'=\frac{(12s^2-16s+4)(4s)-(4s^3-8s^2+4s)(4)}{(4s)^2}= 2s-2$
Division Then Power Rule:
$y = \frac{4s^3-8s^2+4s}{4s}=s^2-2s+1$
$y'=1(2)s^{2-1}-2(1)s^{1-1}+1(0)s^{0-1} = 2s-2$