Answer
$g'(t)=e^{\frac{t}{2}}(2+t)$
Work Step by Step
$g(t)=2te^{\frac{t}{2}}$
Product Rule:
$g'(t)=(2)(e^{\frac{t}{2}})+ (2t)(\frac{1}{2}e^{\frac{t}{2}}) = e^{\frac{t}{2}}(2+t)$
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