Answer
$y' = 1$
Work Step by Step
Quotient Rule:
$y=\frac{x^2-2ax+a^2}{x-a}$
$y' = \frac{(2x-2a)(x-a)-(x^2-2ax+a^2)(1)}{(x-a)^2} = 1$
Division then Power Rule:
$y=\frac{x^2-2ax+a^2}{x-a}=\frac{(x-a)^2}{x-a} = x-a$
$y' = 1$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 32
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