Answer
$f'(w) = 2w$
Work Step by Step
Quotient Rule:
$f(w) = \frac{w^3-w}{w}$
$f'(w) = \frac{(3w^2-1)(w)-(w^3-w)(1)}{w^2} = 2w$
Division Then Power Rule:
$f(w) = \frac{w^3-w}{w} = w^2-1$
$f'(w) = 1(2)w^{2-1}-1(0)w^{0-1} = 2w$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 29
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