Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 15 - Multiple Integrals - 15.3 Double Integrals in Polar Coordinates - 15.3 Exercises - Page 1055: 15

Answer

$A$ = $\frac{\pi}{12}$

Work Step by Step

$A$ = $\int_{-\frac{\pi}{6}}^{\frac{\pi}{6}}\int_0^{\cos3θ}rdrdθ$ $A$ = $2\int_{0}^{\frac{\pi}{6}}\int_0^{\cos3θ}rdrdθ$ $A$ = $\int_{0}^{\frac{\pi}{6}}[r^2]_0^{\cos3θ}dθ$ $A$ = $\int_{0}^{\frac{\pi}{6}}[\cos^2{3θ}]dθ$ $A$ = $\frac{1}{2}\int_{0}^{\frac{\pi}{6}}[1+\cos6θ]dθ$ $A$ = $\frac{1}{2}[θ+\frac{1}{6}\sin 6θ]_{0}^{\frac{\pi}{6}}$ $A$ = $\frac{1}{2}[\frac{\pi}{6}+\frac{1}{6}\sin{\pi}]$ $A$ = $\frac{\pi}{12}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.