Answer
$-1$
Work Step by Step
$\int_R^1{\ln{x}dx}$ = $x\ln{x}|_R^1$ = $R-1-R\ln{R}$
$\int_0^1{\ln{x}dx}$ = $\lim\limits_{R \to {0^{+}}}$$(R-1-R\ln{R})$ = $-1-\lim\limits_{R \to {0^{+}}}(R\ln{R})$ = $-1$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 8 - Techniques of Integration - 8.7 Improper Integrals - Exercises - Page 441: 37
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