Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.3 Dot Product and the Angle Between Two Vectors - Exercises - Page 667: 64

Answer

$\sqrt {17}$

Work Step by Step

We have the vectors $v=<8,2>$ and $u=<3,5>$. Then: $\textbf{u}_{\perp \textbf{v}}=\textbf{u}-\textbf{u}_{\parallel \textbf{v}}$ $\textbf{u}_{\parallel \textbf{v}}=(\frac{\textbf{u}\cdot\textbf{v}}{\textbf{v}\cdot\textbf{v}})\textbf{v}=(\frac{3\times8+5\times2}{8^{2}+2^{2}})⟨8,2⟩=⟨4,1⟩$ Then, $\textbf{u}_{\perp \textbf{v}}=⟨3,5⟩-⟨4,1⟩=⟨-1,4⟩$ $||\textbf{u}_{\perp \textbf{v}}||=\sqrt {(-1)^{2}+4^{2}}=\sqrt {17}$
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