Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.4 Exercises - Page 288: 4

Answer

negative

Work Step by Step

Apply Th.4.6 from section 4-3, Additive lnterval Property $\displaystyle \int_{-2}^{2}f(x)dx=\int_{-2}^{0}f(x)dx+\int_{0}^{2}f(x)d$, graphing the integrand function ( image below) we estimate that the two definite integrals on the RHS, each representing an area, are such that the area below the x-axis is greater in magnitude than the area above the x-axis. The sum of integrals on the RHS is negative, so the integral $\displaystyle \int_{-2}^{2}f(x)dx$ is negative
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