Answer
$\pi +2$
Work Step by Step
Evaluate the definite integral using the Fundamental Theorem of Calculus
$\int_0^{\pi} (1+sinx)dx$, Integrate
$[x-cosx]_0^{\pi}$, Evalute the definite integral
$(\pi -- 1) -(-1)$, Simplify
$\pi +2$
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