Answer
$9.5$
Work Step by Step
$\int^2_{1} (6x^2 -3x) $
$ 2x^3 - \frac{3}{2}x^2$, integrate
$ (2x^3 - \frac{3}{2}x^2)]^2_1$, Definite Integral Form
$(16-6)-(2-\frac{3}{2})$, Definite Integral
$9.5$, simplify
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.4 Exercises - Page 288: 10
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