Answer
$-\frac{1}{18}$
Work Step by Step
$\int^1_0 \frac{x-\sqrt x}{3}dx $
$ \frac{1}{3}\int^1_0 (x-\sqrt x) dx$, Rewrite
$\frac{1}{3}(\frac{1}{2}x^2 - \frac{2}{3}x^{\frac{3}{2}})$, Integrate
${\frac{1}{6}x^2 - \frac{2}{9}x^{\frac{3}{2}}}]^1_0 $, Definite Integral Form
$(\frac{1}{6}- \frac{2}{9})-0$, Take Definite Integral
$-\frac{1}{18}$, Simplify
