Answer
$\frac{1}{2}$
Work Step by Step
$\int^2_1 (\frac{3}{x^2}-1)dx$
$\int^2_1 (3x^{-2}-1)dx$, Rewrite
${-3x^{-1} -x}]^2_1$, Integrate
$ (-\frac{3}{2}-\frac{4}{2}) -(-3-1)$, Take Definite Integral
$\frac{1}{2}$, Simplify
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