Answer
$\\g'(x)=m=\frac{3}{2}$
Work Step by Step
$\\g(x)=\frac{3}{2}x+1$
$\\g'(x)=\frac{3}{2}$
$\\g'(-2)=\frac{3}{2}$
The slope of the tangent line to the graph at point (-2,-2) is $\frac{3}{2}$.
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