Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.1 Exercises - Page 103: 29

Answer

$\\y=\frac{1}{2}x+\frac{1}{2}$

Work Step by Step

$\\f(x)=\sqrt x$ $\\f(x)=x^{1/2}$ $\\f’(x)=\frac{1}{2}x^{\frac{-1}{2}}$ $\\f’(x)=\frac{1}{2\sqrt x}$ $\\f’(1)=\frac{1}{2\sqrt 1}$ $\\f’(1)=\frac{1}{2}$ Apply to straight line equation (y-y1)=m(x-x1) $\\y-1=\frac{1}{2}(x-1)$ $\\y-1=\frac{1}{2}x-\frac{1}{2}$ $\\y=\frac{1}{2}x+\frac{1}{2}$
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