Answer
$\\g'(x)=0$
Work Step by Step
$\\g(x)=-3$
$\\g'(x)=\lim\limits_{h \to 0}\frac{-3-(-3)}{h}$
$\\g'(x)=\lim\limits_{h \to 0}\frac{0}{h}$
$\\g'(x)=0$
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