Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.1 Exercises - Page 103: 12

Answer

$\\g'(x)=0$

Work Step by Step

$\\g(x)=-3$ $\\g'(x)=\lim\limits_{h \to 0}\frac{-3-(-3)}{h}$ $\\g'(x)=\lim\limits_{h \to 0}\frac{0}{h}$ $\\g'(x)=0$
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