Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.1 Exercises - Page 103: 15

Answer

$\\h'(s)=\frac{2}{3}$

Work Step by Step

$\\h(s)=3+\frac{2}{3}s$ $\\h'(s)=\lim\limits_{Δs \to 0}\frac{3+\frac{2}{3}(s+Δs)-3-\frac{2}{3}s}{Δs}$ $\\h'(s)=\lim\limits_{Δs \to 0}\frac{3+\frac{2}{3}s+\frac{2}{3}Δs-3-\frac{2}{3}s}{Δs}$ $\\h'(s)=\lim\limits_{Δs \to 0}\frac{\frac{2}{3}Δs}{Δs}$ $\\h'(s)=\lim\limits_{Δs \to 0}\frac{\frac{2}{3}Δs}{Δs}$ $\\h'(s)=\frac{2}{3}$
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