Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 3 - Section 3.10 - Linear Approximations and Differentials. - 3.10 Exercises - Page 259: 25

Answer

$\Delta x = dx = 0.8$ $\Delta y = 0.34164$ $dy = 0.4$ We can see a sketch below.

Work Step by Step

$y = \sqrt{x-2}$ $\Delta x = dx = 0.8$ When $x = 3$, then $y = \sqrt{3-2}= 1$ When $x = 3.8$, then $y = \sqrt{3.8-2} = 1.34164$ $\Delta y = 1.34164-1 = 0.34164$ We can find the value of $dy$: $\frac{dy}{dx} = \frac{1}{2}(x-2)^{-1/2} = \frac{1}{2~\sqrt{x-2}}$ $dy = \frac{1}{2~\sqrt{x-2}}~dx$ $dy = \frac{1}{2~\sqrt{3-2}}~(0.8)$ $dy = 0.4$ We can see a sketch below.
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