Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Review - Exercises - Page 69: 31

Answer

$x=\frac{\ln 3}{2}$ or $x\approx 0.549$

Work Step by Step

$e^{2x}=3$ (Take the natural logarithm) $\ln (e^{2x})=\ln 3$ (Use the property $\ln e^a=a$) $2x=\ln 3$ (Divide by 2) $x=\frac{\ln 3}{2}$ $x=0.5493....$ Thus, the solution is $x=\frac{\ln 3}{2}$ or $x\approx 0.549$.
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