Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Review - Exercises - Page 69: 29

Answer

(a) 25 (b) 3 (c) $\frac{4}{3}$

Work Step by Step

(a) $e^{2\ln 5}=e^{(\ln 5)\cdot 2}=(e^{\ln 5})^2=5^2=25$ (b) $\log_64+\log_654=\log_6(4\cdot 54)=\log_6216=\log_66^3=3$ (c) Let $x=\arcsin \frac{4}{5}$. We have $\sin (x)=4/5$ and so $\cos (x)=3/5$. So, $\tan (\arcsin \frac{4}{5})=\tan (x)=\frac{\sin (x)}{\cos (x)}=\frac{4/5}{3/5}=\frac{4}{3}$
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