Answer
$f^{-1}(6)=1$
Work Step by Step
Substituting $x=1$ into $f(x)$,
$f(1)=2\cdot 1+4^1$
$f(1)=2+4$
$f(1)=6$
Using the property $f(x)=y\Leftrightarrow f^{-1}(y)=x$, we get $f^{-1}(6)=1$.
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Review - Exercises - Page 69: 25
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