Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 1

{$-2,-6$}

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ Given: $x^2+8x+12=0$ Thus, $x=\dfrac{-8 \pm \sqrt{(8)^2-4(1)(12)}}{2(1)}$ or, $x=\dfrac{-8 \pm 4}{2}$ or, $x=\dfrac{-8 + 4}{2}=-2$ and $x=\dfrac{-8 - 4}{2}=-6$ Our solution set is: {$-2,-6$}