Answer
FALSE. The equation with solution set {$2,5$} is $(x - 2)(x - 5) = 0$.
Work Step by Step
FALSE
Plug in the roots $πΌ=2$ and $π½=5$ to the quadratic equation: $x^2β(πΌ+π½)x+πΌπ½=0$
$x^2β(2+5)x+(2β
5)=0$
$x^2β7x+10=0$ which can be factored into:
$(x-2)(x-5)$
$(x - 2)(x - 5) = 0$