Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 14

{$-3 - 2i,-3 + 2i$}

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ Since, $x^2+6x+13=0$ Thus, $x=\dfrac{-(6) \pm \sqrt{(6)^2-4(1)(13)}}{2(1)}$ or, $x=\dfrac{-6 \pm \sqrt{-16}}{2}$ or, $x=-3 \pm 2i$ or, $x=-3 - 2i,-3 + 2i$ Our solution set is: {$-3 - 2i,-3 + 2i$}