Answer
$x=+\sqrt{\dfrac{5}{3}},-\sqrt{\dfrac{5}{3}}$
Work Step by Step
Given: $3x^2-5=0$
This can be written as: $3x^2=5$
or, $x^2=\dfrac{5}{3}$
Apply The Square Root Property. $x=\pm \sqrt{\dfrac{5}{3}}$
Hence, $x=+\sqrt{\dfrac{5}{3}},-\sqrt{\dfrac{5}{3}}$
