Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 592: 13

Answer

The solutions are $ 3 ± \sqrt 5$, and the solution set is {${3+\sqrt 5, 3-\sqrt 5}$} or {$ 3 ± \sqrt 5$}.

Work Step by Step

$(x - 3)^2 = 5$ Using the Square Root Property $u^2 = d$, then $u = \sqrt d$ or $u = - \sqrt d$. Thus, $x - 3 = \sqrt 5$ or $x - 3 = -\sqrt 5$ The solutions are $ 3 ± \sqrt 5$, and the solution set is {${3+\sqrt 5, 3-\sqrt 5}$} or {$ 3 ± \sqrt 5$}.
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