Answer
$x=\pm \sqrt {6}$ or, $x=+\sqrt {6},-\sqrt {6}$
Work Step by Step
Given: $7x^2=42$
This can be written as: $x^2=\dfrac{42}{7}$
or, $x^2=6$
Apply The Square Root Property.
$x=\sqrt{6}$
Hence, $x=\pm \sqrt {6}$ or, $x=+\sqrt {6},-\sqrt {6}$
