Answer
$x=\pm \dfrac{5}{4}$ or, $x=+\dfrac{5}{4},-\dfrac{5}{4}$
Work Step by Step
Given: $16x^2=25$
This can be written as: $x^2=\dfrac{25}{16}$
or, $x^2=\dfrac{25}{16}$
Apply The Square Root Property.
$x=\sqrt{\dfrac{25}{16}}$
Hence, $x=\pm \dfrac{5}{4}$ or, $x=+\dfrac{5}{4},-\dfrac{5}{4}$
