Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 592: 12

Answer

{$-11,5$}

Work Step by Step

Given: $(x+3)^2=64$ Apply The Square Root Property. This can be written as: $(x+3)=\sqrt{64}$ or, $(x+3)=\pm 8$ or, $x=-3+8,-3-8$ or,$x=5,-11$ Hence, solution set is $x=${$-11,5$}
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