Answer
$x=+\sqrt{\dfrac{2}{3}},-\sqrt{\dfrac{2}{3}}$
Work Step by Step
Given: $3x^2-2=0$
This can be written as: $3x^2=2$
or, $x^2=\dfrac{2}{3}$
Apply The Square Root Property. $x=\pm \sqrt{\dfrac{2}{3}}$
Hence, $x=+\sqrt{\dfrac{2}{3}},-\sqrt{\dfrac{2}{3}}$
