Answer
$x=\pm \dfrac{7}{2}$ or, $x=+\dfrac{7}{2},-\dfrac{7}{2}$
Work Step by Step
Given: $4x^2=49$
This can be written as: $x^2=\dfrac{49}{4}$
or, $x^2=\dfrac{49}{4}$
Apply The Square Root Property.
$x=\sqrt{\dfrac{49}{4}}$
Hence, $x=\pm \dfrac{7}{2}$ or, $x=+\dfrac{7}{2},-\dfrac{7}{2}$
