Answer
$-1$
Work Step by Step
RECALL:
(1) $a^{mn} = (a^m)^n$
(2) $i^2=-1$
(3) $a^{m+n} = a^m \cdot a^n$
Use rule (1) above to obtain:
$=(i^2)^{11}$
Use rule (2) to obtain:
$=(-1)^{11}
\\=(-1)(-1)(-1)(-1)(-1)(-1)(-1)(-1)(-1)(-1)(-1)
\\=-1$
