Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 570: 43

Answer

$3+36i $.

Work Step by Step

The given expression is $=(6-3i)(-2+5i)$ Use the FOIL method. $=(6)\cdot(-2)+(6)\cdot(5i) + (-3i)\cdot(-2)+(-3i)\cdot(5i)$ Simplify. $=-12+30i +6i-15i^2$ Use $i^2=-1$ $=-12+30i +6i+15$ Add like terms. $=3+36i $.
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