Answer
$14+29i$
Work Step by Step
RECALL:
(1)
$(a+b)(c+d)
\\= a(c+d) + b(c+d)
\\=ac+ad + bc + bd$
(2) $i^2=-1$
Use rule (1) above to obtain:
$=4(5+6i) + i(5+6i)
\\=4(5) + 4(6i) + i(5) + i(6i)
\\=20+ 24i+5i+6i^2
\\=20 + 29i+6i^2$
Use rule (2) above to obtain:
$=20+29i+6(-1)
\\=20+29i+(-6)
\\=20+29i-6
\\=14+29i$
