Answer
$-\dfrac{7}{3}i$
Work Step by Step
Multiply both the numerator and the denominator by the conjugate of the denominator, which is $-3i$, to obtain:
$=\dfrac{7(-3i)}{3i(-3i)}
\\=\dfrac{-21i}{-9i^2}$
Use the fact that $i^2=-1$ to obtain:
$=\dfrac{-21i}{-9(-1)}
\\=\dfrac{-21i}{9}
\\=-\dfrac{21}{9}i
\\=-\dfrac{7}{3}i$
