Answer
$-6\sqrt{3}$
Work Step by Step
RECALL:
(1) $\sqrt{-1}=i$
(2) $i^2=-1$
(3) $\sqrt{ab} = \sqrt{a} \cdot \sqrt{b}$
Simplify each radical by using rules (1) and (3) above:
$=\sqrt{3(-1)} \cdot \sqrt{36(-1)}
\\=(\sqrt{3} \cdot \sqrt{-1}) \cdot \sqrt{6^2(-1)}
\\=(\sqrt{3} \cdot i) \cdot 6\sqrt{-1}
\\=i\sqrt{3} \cdot 6i
\\=6i^2\sqrt{3}$
Use rule (2) above to obtain:
$=6(-1)\sqrt{3}
\\=-6\sqrt{3}$
