Answer
$13+i\sqrt{3}$
Work Step by Step
Factor the radicand so that one factor $-1$ to obtain:
$=13+\sqrt{3(-1)}$
RECALL:
(1) $\sqrt{ab} = \sqrt{a} \cdot \sqrt{b}$
(2) $\sqrt{-1} = i$
Use rule (1) above to obtain:
$=13+ \sqrt{3} \cdot \sqrt{-1}$
Use rule (2) above to obtain:
$=13+\sqrt{3} \cdot i
\\=13+i\sqrt{3}$
