Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 590: 9

Answer

$x =\dfrac{\log{3}}{\log{4}} - 7 \\x \approx -6.2075$

Work Step by Step

Take the common logarithm of both sides to have: $\log{4^{x+7}}=\log{3}$ Apply the power property of logarithms to have: $(x+7)(\log{4}) = \log{3}$ Divide $\log{4}$ to both sides to have: $\\x+7 = \dfrac{\log{3}}{\log{4}}$ Subtract $7$ to both sides to have: $\\x =\dfrac{\log{3}}{\log{4}} - 7 \\x \approx -6.2075$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.