Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 590: 25

Answer

$x=\{ -1,4 \}$

Work Step by Step

Since $y=b^x$ is equivalent to $\log_b y=x$, then the given equation, $ \log_4 (x^2-3x)=1 ,$ is equivalent to \begin{array}{l}\require{cancel} x^2-3x=4^1 .\end{array} Using concepts of quadratic equations, the solutions to the equation above are \begin{array}{l}\require{cancel} x^2-3x=4 \\\\ x^2-3x-4=0 \\\\ (x-4)(x+1)=0 \\\\ x=\{ -1,4 \} .\end{array} Upon checking, both solutions satisfy the original equation. Hence, $ x=\{ -1,4 \} .$
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