Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 590: 28

Answer

$x=\dfrac{\ln8}{2}$

Work Step by Step

Taking the natural logarithm of both sides, the given equation, $ e^{2x}=8 ,$ is equivalent to \begin{array}{l}\require{cancel} \ln e^{2x}=\ln8 .\end{array} Using the properties of logarithms and that $\ln e=1$, the solution to the equation above is \begin{array}{l}\require{cancel} 2x\ln e=\ln8 \\\\ 2x(1)=\ln8 \\\\ 2x=\ln8 \\\\ x=\dfrac{\ln8}{2} .\end{array}
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